Do you want to know coloumbs law of electrostatic?
Coloumbs first law,
i)Same charges repel to each other.
ii)Opposite charges attract to each other.
Coloumbs second law ,
Force between two charges is directly proportional to
i) Multiplication of two charges.
ii)Inverse square of the distance.
Elaborating coloulmbs second law.
Consider two charges Q1 and Q2.
ie, F ∝Q1*Q2 ---------->second law (i).
F∝1/d^2 ---------------≻second law(ii).
F∝ Q1Q2/d^2
F=k. Q1Q2 /d^2
K is constant,so its value is
1➗4ㄫεoεr
εo=absolute permittivity of vaccum or air
=8.854*10^-12 farad/meter
εr=relative permittivity of the medium.
(value is 1 for air or vaccum medi)
F=q1q2 ➗(4πεoεr)
F= q1q2 ➗(4π*8.854*10^-12*εr*d^2)
while elaborating the condition,we get
F=(9*10^9*Q1Q2)/(d2)
Problem-1
A charge of 10micro coloumb is placed 100cm away from a charge of 50 micro coloumb in a medium of relative permittivity,4.5.Calculate the force between them.
solution .
Q1=10 uc =10*10^-6 c
Q2=50uc =10*10^-6 c
d=100cm =100*10^-2 m
εr=4.5
F= q1q2 ➗(4π*8.854*10^-12*εr*d^2)
=(10*10^-6*10*10^-6)➗( 4π8.854*10^-12*4.5 (100*10^-2)^2)
F= 1N
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